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Every np language is decidable

WebMar 8, 2011 · A language is Recognizable iff there is a Turing Machine which will halt and accept only the strings in that language and for strings not in the language, the TM either rejects, or does not halt at all. Note: there is no requirement that the Turing Machine should halt for strings not in the language. A language is Decidable iff there is a ... WebMore formally, an undecidable problem is a problem whose language is not a recursive set; see the article Decidable language. There are uncountably many undecidable ... (determining whether it halts for every starting configuration). Determining whether a Turing machine is a ... Algorithms from P to NP, volume 1 - Design and Efficiency ...

Does every Turing-recognizable undecidable language have a NP …

WebMay 10, 2016 · Partially decidable or Semi-Decidable Language -– A decision problem P is said to be semi-decidable (i.e., have a semi-algorithm) if the language L of all yes … WebQuestion: 1. True or False. T = true, F = false, and O = open, meaning that the answer is not known science at this time. In the questions below, P and NP denote P-TIME and NP-TIME, respectively. (i) — Every language generated by an unambiguous context-free grammar is accepted by some DPDA. (ii) — The language {a"b"c" d n >0} is recursive. tampa yacht charter rental https://triplebengineering.com

Decidability and Undecidability in TOC - GeeksforGeeks

WebAnswer (1 of 4): As others have mentioned, the answer is obviously No if P=NP, and not-obviously Yes if P\neqNP, thanks to Ladner’s Theorem. What is perhaps more … WebJun 28, 2024 · 1. The complement of every Turning decidable language is Turning decidable 2. There exists some language which is in NP but is not Turing decidable 3. … Web9. Does every Turing-recognizable undecidable language have a NP-complete subset? The question could be seen as a stronger version of the fact that every infinite Turing … tampa yacht and country club menu

Answers to True/False Questions, Part I

Category:If $P \\ne NP$, is every language not contained in $NP

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Every np language is decidable

GATE GATE-CS-2015 (Set 2) Question 65 - GeeksforGeeks

WebModified 8 years, 10 months ago. Viewed 3k times. 1. All decision problems (i.e.language membership problems), which are verifiable in polynomial time by a deterministic Turing … WebThe question could be seen as a stronger version of the fact that every infinite Turing-recognizable language has an ... of the fact that every infinite Turing-recognizable language has an infinite decidable subset. cc.complexity-theory; np-hardness; ... of 0's). Mahaney's theorem says that no unary language can be NP-complete unless P=NP. ...

Every np language is decidable

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WebJul 15, 2011 · 17. (1) Yes, there are decision problems that are decidable but not in NP. It is a consequence of the time hierarchy theorem that NP ⊊ NEXP, so any NEXP-hard problem is not in NP. The canonical example is this problem: Given a non-deterministic Turing machine M and an integer n written in binary, does M accept the empty string in at most n ... WebDe nition 2 Analogous to P and NP, we have that for every O f0;1g, PO is the set containing all languages decidable by a polynomial-time deterministic oracle Turing Machine with oracle access to O. It follows that NPOis the set containing every language that can be decided by a polynomial-time nondeterministic Turing machine with oracle access ...

Web“Turing recognizable” vs. “Decidable” L(M) –“language recognized by M” is set of strings M accepts Language is Turing recognizable if some Turing machine recognizes it •Also called “recursively enumerable” Machine that halts on all inputs is a decider. A decider that recognizes language L is said to decide language L Web(i)Every language reduces to itself. True. By trivial reduction. (j)Every language reduces to its complement. False. A TM can not reduce to its complement. 2.(10 points) Determine whether the following languages are decidable, recognizable, or undecidable. Brie y justify your answer for each statement. (a) L 1 = fhD;wi: Dis a DFA and w62L(D)g ...

WebFeb 19, 2014 · $\begingroup$ A good pool for examples of nontrivial membership in NP may come from problems for which it has been open for some time whether they were even decidable. Two problems from the top of my hat : string graph recognition and unknot recognition (and the more general knot genus). In both cases though, there does exist a … WebI had the following idea: Because SAT is NP-complete, every language in NP can be reduced to it using a polynomial-time reduction. Therefore, every language in NP can be …

Webevery A in NP is polynomial time reducible to B (p. 304) Theorem 7.35. If B is in NP-complete and B in P, then P = NP Any member can be converted to any other by series of polynomial time f (p. 304) Theorem 7.36. If B in NP-complete, and B≤ P C for some C in NP, then C is also NP-complete Since B is NP-complete, every language in NP is

WebIt remains unknown whether NP=EXP, but it is known that P⊊EXP. Prove that NP ⊆ EXP. In other words, any efficiently verifiable language is decidable, in exponential time. Hint: For a; Question: Let EXP be the class of all languages that are decidable in exponential time, i.e., in time O(2nk) for some constant k (where n is the input size ... tampax tampon shortage 2021WebAlternatively, NP can be defined using deterministic Turing machines as verifiers. A language L is in NP if and only if there exist polynomials p and q, ... Whether these … tygarts creek gageWeb(xxi) T Every NP language is decidable. 1 (xxii) T The intersection of two NP languages must be NP. ... T If L is RE and also co-RE, then L must be decidable. (lvii) T Every language is enumerable. (lviii) F If a language L is undecidable, then there can be no machine that enumerates L. tampax wholesale distributors